The line 2x - y + 4 = 0 cuts the parabola y2 = 8x in P and Q. The midpoint of PQ is
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Refer to the above attachments (3) for the required solution.
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Given that the line 2x - y + 4 = 0 cuts the parabola y2 = 8x at P, Q. We need to find the midpoint of PQ.
Substituting y = 2x + 4 in the equation of parabola.
⇒ (2x + 4)2 = 8x
⇒ 4x2 + 16x + 16 = 8x
⇒ 4x2 + 8x + 16 = 0
⇒ x2 + 2x + 4 = 0
Let x1, x2 be the roots. Then, x1 + x2 = - 2
Now substituting
in the equation of the line we get,
⇒ y2 - 4y + 16 = 0
Let y1, y2 be the roots. Then, y1 + y2 = 4
Let us assume P be (x1, y1) and Q be (x2, y2) and R be the midpoint of PQ.
⇒ R = (- 1, 2)
∴The correct option is C
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