Question

the line 4x-3x+k=0 touches the circle x^2+y^2-4x-8y-5=0 then k is​

Answer 1

Answer:

If line 4y−3x+λ=0 touches the circle x

2

+y

2

−4x−8y−5=0 then distance of its centre from the line is equal to its radius.

Centre is (−2,−4)

radius =

4+16+5

=

25

=5 units

∴ 5=

a

2

+b

2

ax

1

+by

1

+c

5=

16+9

∣6−16+λ∣

⇒5=

5

∣−10+λ∣

⇒

5

λ−10

=±5⇒λ−10=25

⇒λ=10+10=35

5

λ−10

=−5⇒λ−10=−25⇒λ=−15

∴ λ=−15,25

Step-by-step explanation:

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Answer 2

Answer:

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