The line 4x + 3y -12=0 cuts the coordinate axes at A and B. The area of ∆AOB will be.?
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|•αηsωεя•|
c^2=5
=> c= (5)^1/2
x/t + yt= 2(5)^1/2
At x=0
Y=2(5^1/2)/t
At y=0
x=2(5^1/2)t
Area of triangle = 1/2 * x* y
Area = 10 sq unit
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