Question

the line 4x-3y+12= 0 meet the x-axis at A. write down the coordinates of A. determine the equation of the line passing through A and perpendicular to 4x-3y+12=0

Answer 1

HEYA!!!

Your solution is in the attechment.

#KEVIN
HOPE IT HELPS YOU ☺

Answer 2

Here is ur answer dear...............
if the line 4x-3y+12=0 meet the X axis then the Y co-ordinate is zero
so,
put the value of Y zero
4x-0+12=0
4x=-12
x=-3
so the point A obtain is {-3,0}
now we need to find equation of a line passing through this point so , we must need to find the slope of that line so as to find out the equation ...
line is perpendicular to line 4x-3y+12 =0
slope of this line =-a/b
                           =-4/-3
                           =4/3
hence as we know that if lines are parallel than product of their slopes is -1
so slope of the line which  passes through point  A is -3/4
so according to the formula of equation of line
m(x-x1)=(y-y1)
-3/4(x+3)=(y-0)       (point is( -3,0))
-3x-9=4y
3x+4y+9=0   (required equation of the line ................)
HOPE THIS HELPS UH
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