Question

The line 4x + 3y = 12 meets x-axis at the point​

Answer 1

Answer:

Given line : 4x−3y+12=0

When the line meets the x -axis, its y co-ordinate becomes 0.

So, putting y=0 in the given equation, we get

$\sf4x−3(0)+12=0\\ \\ \sf \implies4x+12=0 \\ \\\sf \implies x= 4−12 \\ \\ \sf \implies\red{x=−3}$

Hence, the line meets the x- axis at A(−3,0).