Question

the line current of a 3 phase alternator delivering 5MW and working at 0.8 p.f. is​

Answer 1

Answer:

I don't know sorry

Explanation:

I don't know sorry

Answer 2

Line current of a 3 -phase alternator is given by:

$I_{L} =\frac{S}{\sqrt{3}V_{L} }$

Where S = P/ cosФ            (S = Apparent power)

Given,

P = 5 MW

Power factor = cosФ = P/S

                                S =$\frac{5 MW}{0.8}$

                                 = 6.25 MW

Assume balanced source. so $V_{L}$ = 220 V

$I_{L} =\frac{6.25}{\sqrt{3}\ 220 }$

    = 16401.99 A