Question

The line drawn from the mid-point of one of a triangle parallel to another side, bisect the third side.

Answer 1

SOLUTION

Proof: Let ABC be a ∆ in which D is the mid-point of the side AB & the line DE is drawn parallel to BC meeting AC in E.

We have to prove that E is the mid-point of AC.

=) AE= EC

Now, In ∆ABC,

DE||BC

Then, by thales Theorem

Since, D is the mid-point of AB.

Therefore, AD= DB

From (1) &(2), we get

=) AE= EC

Hence, E bisect AC.

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Answer 2

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