Question

The line equation through point (4, -3) and perpendicular to line 4y-6x + 10 = 0

Answer 1

General form

⤵⤵⤵⤵⤵⤵⤵⤵⤵

y = mx + x

Gradient 1

4y = 6x - 10

y = 6 / 4x - 10/4

y = 3 / 2x - 5/2

gradient = 3/2

Gradient 2

m1 x m2 = - 1

3/2 x m2 = -1

m2 = -1: 3/2

m2 = -1 x 2/3

m2 = -2/3

Line Equations

y = m (x + x1) - y1

y = -2/3 (x + 4) + 3

y = -2 / 3x - 8/3 + 3

3y = -2x - 8 + 9

3y = -2x + 1

Hope it helps ✌

---------------------------------

Mapel = Mathematics

Class = 8 Middle School

Material = Straight line equation

Keywords = equations, gradients

Answer 2

hey mate here is your answer