Math, asked by kautilya1000, 1 year ago

the line given by the equation 2x-y/3=7 passes through the point (k,6) calculate the value of k​

Answers

Answered by Mankuthemonkey01
25

Answer:

9/2

Step-by-step explanation:

Given, the equation of line 2x - (y/3) = 7 passes through a point (k, 6).

To find :- Value of k

Since, the line passes through (k, 6), we can substitute the value of y as 6 and x as k

→ 2x - (y/3) = 7

→ 2k - (6/3) = 7

→ 2k - 2 = 7

→ 2k = 7 + 2

→ 2k = 9

→ k = 9/2

Hence, the value of k is 9/2

→ k = 27/2

Answered by Xsuman682X
8

2x - (y/3) = 7

2k - (6/3) = 7

2k - 2 = 7

2k = 7 + 2

2k = 9

k = 9/2

Hence, the value of k is 9/2

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