Question

The line joining P(-4,5) and Q(3,2 ) intersects the y-axis at R. PM and QN are the perpendiculars from P and Q on the x-axis. Find:
(i) the ratio PR: RQ
(ii) the co-ordinates of R
(iii) the area of the quadrilateral PMNQ.
[PLS BE FAST WITH THE QUESTION AND NO FAKE ANSWERS!]

Answer 1

Answer:

hdydydudydhsowieoehe

Answer 2

R =( 0, y)

1)

0= m1*x2+m2*x1/m1+m2

0 = 3m1-4m2/m1+m2

on cross multiplying

3m1-4m2

m1/m2 = 4/3

:: m1:m2 = 4:3

2)

y= m1*y2+m2*y1/m1+m2

= 4*2+3*5/4+3

= 23/7

Coordinates of R =(0, 23/7)

3)

Area of quadrilateral PMNQ

Quadrilateral obtained is a trapezium

area of trapezium = 1/2*h*(a+b)

= 1/2*MN*(PM+QN)

=1/2*7*(5+2)

= 49/2

= 24.5 Sq units

Note:: length of MN = 7units

length of PM= 5 units

length of QN = 2 units

coordinates of M = (-4, 0)

coordinates of N = (3, 0)