the line joining the mid-points of two chords of a circle passes through its centre . Prove that the chords are parallel .
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We have-
Let AB and CD be the parallel chords of a circle such that M and N are the mid - point of the respective chords.
Since the perpendicular bisector of the chord passes through the centre.
So,
ON is perpendicular to CD.
OM is perpendicular to AB.
Since AB||CD
NOM is a straight line.
Hence the line joining the midpoints of two parallel chords of a circle passes through the center of circle.
Let AB and CD be the parallel chords of a circle such that M and N are the mid - point of the respective chords.
Since the perpendicular bisector of the chord passes through the centre.
So,
ON is perpendicular to CD.
OM is perpendicular to AB.
Since AB||CD
NOM is a straight line.
Hence the line joining the midpoints of two parallel chords of a circle passes through the center of circle.
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