Question

The line joining the points(2,1) (5,-8) is trisected by the points p and q.If the point p lies on the line 2x-y+k=0. Find the value of K​

Answer 1

Answer:

food crops other than grains

Step-by-step explanation:

sugarcanesugarcane it is a tropical as well as subtropical crop it is grown well in hot and humid climate with the temperature of 21 degree Celsius to 27 degree Celsius and an annual rainfall between 75 cm and understand irrigation is required in the region of low rainfall it can be grown on a variety of soils and need manual labourers from sewing to harvesting

Answer 2

$\huge{\dag} \: {\underline{\boxed{\sf{\purple{\mathtt{Solution \ :-}}}}}}$

Let A and B be (2,1) and (5,−8) respectiviey

$\mathsf{ \frac{AP}{AB} = \frac{1}{2} }$

Section Formula:

ㅤㅤㅤㅤㅤIf point (x,y) divides line joining two ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤpoints in$\mathsf{(x{_1},y{_1})}$ and $\mathsf{(x{_2},y{_2})}$ inㅤㅤㅤㅤㅤ ratio m:n internally

Here,

$\mathsf{x{_1}} = 2$

$\mathsf{x{_2}} = 5$

$\mathsf {y{_1}} = 1$

$\mathsf{y{_2}} = ( - 8 )$

$\implies \: \mathsf{x = \frac{mx{_2} + nx{_1}}{m + n} } \: \: \: \: \: \: \: \mathsf{y = \frac{my{_2} + ny{_1}}{m + n} }$

$\implies \mathsf{ x = \frac{5 + 4}{3} } \: \: \: \: \: \: \: \: \: \: \mathsf{y = \frac{ (- 8) + 2}{3} }$

$\mathsf{x,y \subset(3, - 2)}$

The point lies on

$\implies \mathsf{2x - y + k = 0}$

$\implies \mathsf{6 + 2 + k = 0}$

$\implies \mathsf{k = - 8}$

$\huge\mathfrak{\bf{\underline{\underline{\blue{Answer \ :}}}}}$

$\mathsf{ \therefore \: \boxed{ \blue{k = - 8}}}$