Question

The line joining the points (2,-1) and (5,-6) is bisected at p. If p lies on the line 2x+4y+k=0. Find k

Answer 1

p=(7/2,-7/2)
as p lies on the line:
2x+4y+k=0
x=7/2,y=-7/2
put x n y in this eq. and rhen solve the eq. formed you will get the value of k

Answer 2

Answer:

The value of k is 7.

Step-by-step explanation:

The line joining the points (2,-1) and (5,-6) is bisected at p.  The coordinates of p are

$p=(\frac{2+5}{2},\frac{-1-6}{2})=(\frac{7}{2},\frac{-7}{2})$

If p lies on the line 2x+4y+k=0, then the equation must be satisfied by the point p.

$2(\frac{7}{2})+4(\frac{-7}{2})+k=0$

$7-14+k=0$

$-7+k=0$

$k=7$

Therefore the value of k is 7.