Question

The line joining the points (2,-1) and (5,-6) is bisected at P. if P lies on the line 2x+4y+k=0, find the value of k

Answer 1

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Answer 2

Answer:

The value of x is 7.

Step-by-step explanation:

P is midpoint of (2,-1) and (5,-6),

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

$P=(\frac{2+5}{2},\frac{-1-6}{2})$

$P=(3.5,-3.5)$

If point P lies on the line 2x+4y+k=0, then the equation of line must be satisfy by the point.

$2(3.5)+4(-3.5)+k=0$

$7-14+k=0$

$-7+k=0$

$k=7$

Therefore the value of x is 7.