Math, asked by chaitanya08, 8 months ago

the line joining the points 2 ,-1 and 5, -6 is bisected at p .P lies on 2x+4y+k=0 find k​

Answers

Answered by Hiteshbehera74
1

Let P=(x, y)

Using Midpoint formula,

x =  \frac{x1 + x2}{2} ,y =  \frac{y1 + y2}{2}  \\ x =  \frac{2 + 5}{2} ,y =   \frac{ - 1 - 6}{2}  \\ x =  \frac{7}{2} ,y =  -  \frac{7}{2}

Since point P is lying on 2x+4y+k = 0

∴ At ( \frac{7}{2} , -  \frac{7}{2} )

2( \frac{7}{2} ) + 4( -  \frac{7}{2} ) + k = 0 \\ 7 - 14 + k = 0 \\  - 7 + k = 0 \\ ∴k = 7

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