Math, asked by champachameli78, 28 days ago

The line L passes through the points (0, 7) and (3, 19).

Work out the equation of the line L.

please explain

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Answers

Answered by sandhyanairpune
18
Slope of line = m = y2-y1 / x2-x1 = 19-7/3-0 = 12/3 = 4

Equation of line is

(y-y1)=m(x-x1)
(y-7)=4(x-0)
y-7=4x

4x-y+7=0

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Answered by pulakmath007
1

The equation of the line L is 4x - y + 7 = 0

Given :

The line L passes through the points (0, 7) and (3, 19)

To find :

The equation of the line L

Formula Used :

The equation of the line passing through two points ( x₁ , y₁) & (x₂ , y₂) is

\displaystyle \sf{  \frac{y   - y_1}{x   - x_1}= \frac{y_2   - y_1}{x_2   - x_1} }

Solution :

Step 1 of 2 :

Write down the given points

Here it is given that the line L passes through the points (0, 7) and (3, 19)

Step 2 of 2 :

Find equation of the line L

The equation of the line L passing through the points (0, 7) and (3, 19) is given by

\displaystyle \sf   \frac{y - 7}{x - 0}  =  \frac{19 - 7}{3 - 0}

\displaystyle \sf{ \implies }\frac{y - 7}{x }  =  \frac{12}{3 }

\displaystyle \sf{ \implies }\frac{y - 7}{x }  =  4

\displaystyle \sf{ \implies }y - 7 = 4x

\displaystyle \sf{ \implies }4x - y + 7 = 0

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