The Line l1 passes through (9,-4) with gradient 1/3
Find an eqn for l1 in the form ax+by+c=0, where a,b,c are integers.
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Step-by-step explanation:
in the form ax+by+c;
I probably think you first use the general formula y=mx+c i.e. from the gradient=1/3, -4=ax+c
-4=1/3*9+c
-7=c(where m is substituted for a)
Hence; 1/3x + 4 - 7 = 0
Im not sure if this is what you expected but i hope it has helped somehow.
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