The line MN is shown on the grid. Find the equation of the perpendicular bisector of line MN
Answers
Given : The line segment MN is shown on the grid.
M = (- 1 , 7)
N = ( 3 , - 1)
To Find : the equation of the perpendicular bisector of MN
Solution:
perpendicular bisector of MN will passes through the mid point of MN
and slope of perpendicular bisector of MN = - 1/slope of MN
M = (- 1 , 7) , N = ( 3 , - 1)
Mid point = ( - 1 + 3) /2 , ( 7 - 1)/2 = ( 1 , 3)
Slope of MN = ( - 1 - 7) / ( 3 - (-1)) = - 8 /4 = - 2
Slope of perpendicular bisector of MN = - 1/-2 = 1/2
Passed through ( 1 , 3)
Equation of MN
y - 3 = (1/2)(x - 1)
=> 2y - 6 = x - 1
=> x - 2y + 5 = 0
equation of the perpendicular bisector of line MN x - 2y + 5 = 0
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Answer:
Step-by-step explanation:Given : The line segment MN is shown on the grid.
M = (- 1 , 7)
N = ( 3 , - 1)
To Find : the equation of the perpendicular bisector of MN
Solution:
perpendicular bisector of MN will passes through the mid point of MN
and slope of perpendicular bisector of MN = - 1/slope of MN
M = (- 1 , 7) , N = ( 3 , - 1)
Mid point = ( - 1 + 3) /2 , ( 7 - 1)/2 = ( 1 , 3)
Slope of MN = ( - 1 - 7) / ( 3 - (-1)) = - 8 /4 = - 2
Slope of perpendicular bisector of MN = - 1/-2 = 1/2
Passed through ( 1 , 3)
Equation of MN
y - 3 = (1/2)(x - 1)
=> 2y - 6 = x - 1
=> x - 2y + 5 = 0
equation of the perpendicular bisector of line MN x - 2y + 5 = 0
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the coordinates of the points of intersection of lines ax+by=9 and bx+ ...
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Find the equation of the line passing through the origin and which ...
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