The line of intersection of 1 and 2 quadrants is
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Answer:
I ' m not sure but I think
your answer is 0
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Step-by-step explanation:
ANSWER
Let 2x−3y=−3.......(1)
−12=−4x+y
and ⇒−4x+y=−12........(2)
Multiply equation (1) by 2, we get
4x−6y=−6........(3)
Add equation (2) and (3), we get
−5y=−18
⇒y=
5
18
=3.6
Put the value of y=3.6 in equation (1), then
2x−3(3.6)=−3
⇒2x−7.2=−3
]⇒2x=−3+7.2
⇒2x=4.2
⇒x=2.1
So point of intersection of the line is (2.1,3.6)
Both point in Quadrant I
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