Question

The line passing through (0, 1) and perpendicular to the line x - 2y + 11 = 0 is

Answer 1

Answer:

Step-by-step explanation:

x-2y=-11

Let,

x-2y=k

As per que

x=0

Y=1

So

x-2y=k

0-2×1=k

K=-2

Now put the value of k in eq

x-2y=-2

So

New eq of perpendicular is.

-2x+y=-2

Or

2x+y=2

Hope it helps u✌✌

Answer 2

The line perpendicular to x-2y+11=0 is

2x+y+k=0.This is passing through (0,1)

then 0+1+k=0

Therefore k=-1

Hence the equation of required line is

2x+y-1=0