The line passing through 1,1 and parallel to the line 2x - 3y +5=0
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Answer:
2x-3y+1=0
Step-by-step explanation:
Here's a shortcut method:-
If there's a line ax + by + c = 0, then the equation of line parallel to that will be ax + by + λ =0.
Let's use this,
the equation of original line is 2x -3y +5 =0.
then the parallel line will be 2x-3y+λ=0 ....(1)
Now, it is given that line parallel line passing from (1,1).
So we can substitute x= 1 and y=1 in equation (1),
which gives us,
2(1)-3(1)+λ=0
=>λ=1
so, the final answer is
2x-3y+1=0
Hope it helps!
don't forgot to mark it as brainliest.
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