the line passing through (-4,-2)&(2,-3)is perpendicular to the line passing through(a,5)&(2,-1).find a
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let the slope of first line =m
m=(-3+2)/(2+4)=-1/6
slope of the second line =n
n!=(-1-5)/2-a
if lines are perpendicular then mn=-1
(-1/6)(-6/2-a)=-1
1=-(2-a)
1=a-2
a=3
m=(-3+2)/(2+4)=-1/6
slope of the second line =n
n!=(-1-5)/2-a
if lines are perpendicular then mn=-1
(-1/6)(-6/2-a)=-1
1=-(2-a)
1=a-2
a=3
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