The line passing through A(-2,3) and B(4,b) is perpendicular to the line 2x-4y=5. Find the value of b.
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slope of A( -2,3) And B( 4,b)
is ( b-3)/ ( 4 -(-2))
b-3)/ 4+2
b-3)/6
Now as its perpendicular to 2x- 4y = 5
Slope of 2 x-4y = 5 is ( 2/4) = 1/2
Now if 2 lines are perpendicular having slope m1 and m2
then m1× m2 = -1
So
( b-3)/6. × 1/2 = -1
b-3)/6 = -2
b-3 = -12
b= -12 +3 = -9
Anonymous:
Thnx alot.....very helpful
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