The line passing through the extremity a of the major axis and extremity b of the minor axis of the ellipse x2 + 9y2 = 9 meets its auxiliary circle at the point m. Then the area of the triangle with vertices at a, m, and o (the origin) is
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Correct option is
C
10
27
The equation of ellipse is
9
x
2
+y
2
=1
The length of semi-major axis is a=3 and the length of semi-minor axis is b=1
The coordinates of point A is (3,0) and the coordinates of point B is (0,1)
The equation of line passing through A,B is x+3y=3
The equation of an auxiliary circle of an ellipse is x
2
+y
2
=9
The line AB cuts x
2
+y
2
=9 at point M
By solving the above equations
The coordinates of point M are (−
5
12
,
5
9
)
The area of triangle AMO is
2
1
∣0(0−
5
9
)+3(
5
9
−0)−
5
12
(0−0)∣=
10
27
solution
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