The line PDQ is a tangent to the circle ABCD, at the point D The chords BD and AC intersects at R, and LPDC = 50°, LCDB = 30° and LARD = 70°. Find, stating your reasons, the size of angles in degrees.
a) ZACD
b) ZACB
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Answer:
Since BD is a diameter of the circle.
∴∠BAD=90
∘
and also ∠BCD=90
∘
∠DBC=∠DCQ=40
∘
[∠s in the alternate segments]
∠BCP+∠BCD+∠DCQ=180
∘
⇒∠BCP+90
∘
+40
∘
=180
∘
∠BCP=50
∘
Similarly from ΔBAD,60
∘
+∠BAD+∠ADB=180
∘
⇒60
∘
+90
∘
+∠ADB=180
∘
∠ADB=30
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