Question

the line PQ parallel to the side BC. Find the lengths of PB,AQ, QC.
AP=5cm, PB=AQ, AP/PB=1/2​

Answer 1

Answer:

According to question,

PBAP=QCAQ=21        [basic proportionality theorem]

21=QC3

QC =6

Hence, AC = AQ + QC = 3+6=9 cm 

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Answer 2

Answer:

AP = 5 cm

AP/PB = 1/2

2 AP = PB

5*2 = PB

PB = 10 cm

PB = AQ

AQ = 10 cm

Using Basic Proportionality Theorem,

AP/PB = AQ/QC

5 cm / 10 cm = 10 cm / QC

QC = 5 cm