Question

The line represented by the equation 4x + 5y – 20 = 0 cuts y-axis at the point
(A) (0, -5)
we (0,4)
(B) (0, 4)
(D) (0,5)​

Answer 1

1 is the correct option according to your question

Answer 2

Answer:

Step-by-step explanation:

Concept : If a straight line $ax + by + c = 0$ passes through y axis only then x = 0.

Solution:

the given equation of line is $4x + 5y - 20 = 0$

for the point that passes through y axis,

putting x = 0 in the equation of the line,

$4 * 0 + 5y - 20 = 0$

⇒ $5y = 20$ ⇒ $y = 4$

∴ The point where the line $4x + 5y - 20 = 0$ cuts y-axis is $(0 , 4)$.

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