Question

The line segment AB meets the coordinates axes in points A and B. If point P(3,6) divides AB in the ratio 2:3,then find the points A and B​

Answer 1

The line segment AB meets the coordinates axes in points A and B. point P(3, 6) divides AB in the ratio of 2 : 3.

To find : find the points A and B.

solution : since the line segment AB meets the coordinates axes in points A and B, we can assume point A = (x, 0) and B = (0, y).

now using section formula,

P = [(mx₂ + nx₁)/(m + n), (my₂ + ny₁)/(m + n)]

here, P = (3, 6) , m : n = 2 : 3

(x₁, y₁) = (x, 0) and (x₂ , y₂) = (0, y)

now (3, 6) = [(2 × 0 + 3 × x)/(2 + 3), (2 × y + 3 × 0)/(2 + 3)]

⇒(3, 6) = [3x/5 , 2y/5]

3 = 3x/5 ⇒x = 5

and 6 = 2y/5 ⇒y = 15

Therefore points A (5, 0) and B (0, 15)

Answer 2

Answer:

here is the problem

Step-by-step explanation:

exercise 7.2 12th problem