Question

the line segment joining the point p(3,3) and q (6,-6) is trisected at points A and B such that A is nearer to P. if A lies given by 2x+y+k =0 find the value of K. with draw plz (solve krke photo bhej do koi) ​

Answer 1

P(3,3),Q(6,-6)

PA=AB=BO

PA:AO=1:2

The coordinates of A are given to be

(1×6+2×3/1+2,1×(-6)+2×3/1+2)

(6+6/3,-6+6/3)

(12/3,0/3)=(4,0)

2x+y+k=0 passes through A therefore,

2(4)+0+k=0

8+k=0

k=-8

Answer 2

Step-by-step explanation

sorry i dont know