Question

The line segment joining the points (3, -1) and (-6, 5) is trisected. The coordinates of one of the point of trisection are. plzz answer as quickly as possible​

Answer 1

Step-by-step explanation:

the co-ordinates of point P is (0,1) ; Q is (-3,3)

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Answer 2

Given

$(x_{1} ,y_{1} )=(3,-1)\\(x_{2},y_{2})=(-6,5)$

Here we are calculating the point of trisection,

meaning of trisection is that, dividing a line segment in three different parts or line segments in the 2:1

m:n=2:1

for that, we are using the following equation,

Cordinate =$(\frac{mx_{2}+nx_{1} }{m+n} ,\frac{my_{2}+ny_{2} }{m+n} )$

substituting the value in the above equation

Cordinate =$(\frac{-6*2+3*1}{2+1} ,\frac{5*2+1(-1)}{2+1} )$

so calculate the  above equation,

Cordinate=

= $(\frac{-12+3}{3} ,\frac{10-1}{3} ),\\(\frac{-9}{3} ,\frac{9}{3} ),\\(-3,3),$

Hence the point of trisection are $(3,-3)$