The line segment joining the points (8,-1) and (-6,5) is insected. the coordinates of point of trisection are
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Answer:
(6,−4,−2)
Step-by-step explanation:
Given coordinates of P as (4,2,−6) and Q as (10,−16,6)
Let R and S be the points of trisection of line segment PQ.
Then R divides PQ in the ratio 1:2 and S is the mid-point of RQ.
Let the coordinates of R be (x,y,z)
By using section formula,
x=
1+2
1(10)+2(4)
,y=
1+2
1(−16)+2(2)
,z=
1+2
1(6)+2(−6)
⇒x=
3
18
,y=
3
−12
,z=
3
−6
⇒x=6,y=−4,z=−2
So, the coordinates of R are (6,−4,−2)
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