Question

the line segment joining the points A(4,8) and B (6,10) has a third point c on it such that line passing through c is equidistant from a and b the length of bc is equal to

Answer 1

X1=6 X2=4
Y1=10 Y2=8


Distance of AB=
$\sqrt{( {x}^{2} - {x}^{1}) + ({y }^{2} - {y}^{1}) } \\ \sqrt{( {6}^{2} - {4 }^{2} ) + ( {10}^{2} - {8}^{2} ) } \\ \sqrt{ {2}^{2} + {2}^{2} } = \sqrt{4 + 4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{8} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \sqrt{2}$

Answer 2

The answer for this question is root 2.