Question

The line segment joining the points P(3, 3) and Q(6, -6) is trisected at the points
A and B such that A is nearer to P. If A also lies on the line given by 2x + y + k =
0, find the value of k.

Answer 1

l can't not understand your quedtion

Answer 2

P and Q are points of trisection and P is nearer to A

⟹AP:PB=1:2

So, P=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

⟹(

1+2

1(5)+2(2)

,

1+2

1(−8)+2(1)

)

⟹P(−3,2) pasees through 2x−y+k=0

⟹k=8

Hope it helps and follow me