The line that passes through the point (1, 4) and is perpendicular to the line 3x + 2y - 5 = 0
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line perpendicular to 3x+2y -5=0 is 2x-3y+k=0
it passes through (1,4)
2(1)-3(4)+k=0
2-7+k=0
k=5
hence required line is 2x-3y+5=0
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