Math, asked by Superstar111, 1 year ago

the line through A (-2,3) and B (4, b) is perpendicular to the line 2x-4y=5. find the value of b.

Answers

Answered by Anonymous
82
slope of line AB = y2-y1/x2 - x1
m = b-3/4+2
m=b-3/6

equation of line 2x-4y=5
divide through5 by -4
-x/2 +y = -5/4
y= x/2 - 5/4
on comparing with y=MX+c
we get slope of line ,say m2
m2=1/2
b
if two lines are perpendicular then product of their slope will be -1
1/2 × b-3/6 =-1
b-3 = -12
b=-9
Answered by ananyabhattacharya58
2

Answer:

The slope of line AB is

4+2

b−3

=

6

b−3

Again, slope of line 2x−4y=5 is

2

1

Since line AB is perpendicular to 2x−4y=5

m

1

m

2

=−1

6

b−3

×

2

1

=−1

⇒b−3=−12

⇒b=−9

Step-by-step explanation:

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