the line through A (-2,3) and B (4, b) is perpendicular to the line 2x-4y=5. find the value of b.
Answers
Answered by
82
slope of line AB = y2-y1/x2 - x1
m = b-3/4+2
m=b-3/6
equation of line 2x-4y=5
divide through5 by -4
-x/2 +y = -5/4
y= x/2 - 5/4
on comparing with y=MX+c
we get slope of line ,say m2
m2=1/2
b
if two lines are perpendicular then product of their slope will be -1
1/2 × b-3/6 =-1
b-3 = -12
b=-9
m = b-3/4+2
m=b-3/6
equation of line 2x-4y=5
divide through5 by -4
-x/2 +y = -5/4
y= x/2 - 5/4
on comparing with y=MX+c
we get slope of line ,say m2
m2=1/2
b
if two lines are perpendicular then product of their slope will be -1
1/2 × b-3/6 =-1
b-3 = -12
b=-9
Answered by
2
Answer:
The slope of line AB is
4+2
b−3
=
6
b−3
Again, slope of line 2x−4y=5 is
2
1
Since line AB is perpendicular to 2x−4y=5
m
1
m
2
=−1
⇒
6
b−3
×
2
1
=−1
⇒b−3=−12
⇒b=−9
Step-by-step explanation:
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