the line through origin meets the line 2x=3y+13 at angles at point Q.Find the co ordinates of Q
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Equation of a line with slope m-
y=mx+c⟶(i)
Equation of line L
1
-
2x=3y+13{Given}
⇒3y=2x−13
⇒y=
3
2
x−
3
13
⟶(ii)
Comparing eq
n
(i)&(ii), we have
slope of line L
1
(m
1
)=
3
2
Let another line be L
2
with slope m
2
.
As both the line L
1
&L
2
meets at right angle at point Q.
∴m
1
.m
2
=−1
⇒m
2
=
m
1
−1
⇒m
2
=
(
3
2
)
−1
{∵m
1
=
3
2
}
⇒m
2
=
2
−3
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