Question

The line through points (-2,3) and B(4,b) is perpendicular to line 2x-4y=5. Find the value of b

Answer 1

Hlw mate!!


Slope of line AB = y2-y1/x2 - x1
m = b-3/4+2
m=b-3/6

equation of line 2x-4y=5
divide through5 by -4
-x/2 +y = -5/4
y= x/2 - 5/4
on comparing with y=MX+c
we get slope of line ,say m2
m2=1/2
b
if two lines are perpendicular then product of their slope will be -1
1/2 × b-3/6 =-1
b-3 = -12
b=-9


Hope it helpful

Answer 2

Answer

Slope of line AB = y2-y1/x2 - x1
m = b-3/4+2
m=b-3/6

equation of line 2x-4y=5
divide through5 by -4
-x/2 +y = -5/4
y= x/2 - 5/4
on comparing with y=MX+c
we get slope of line ,say m2
m2=1/2
b
if two lines are perpendicular then product of their slope will be -1
1/2 × b-3/6 =-1
b-3 = -12
b=-9

Hope it helpful