The line with the equation 6x-4y = 12 intersects the x axis at point A. The coordinates of point A are
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DISCUSSION
In a straight line equation, a line can cut the x axis and / or y axis. If the line intersects the x axis, then the resulting coordinate point is (x, 0). As for the line that intersects the y axis, the coordinate points that intersect the y axis are (0, y).
To find the coordinates of the point that intersects the x axis, we enter 0 as the y value in the existing line equation. The known line equation is 6x - 4y = 12.
Enter 0 as the y value and finish it in an algebraic way.
6x - 4y = 12
6x = 12 + 4y
6x = 12 + 4 (0)
6x = 12 + 0
x = 12/6
x = 2
Note: if you positively move a segment, it will change to negative. If multiplication moves segments, it will change to division.
We have got the x value, which is 2. Enter into the model the coordinate point that intersects the x axis.
The coordinate point that intersects the x axis
= (x, 0)
= (2, 0)
So, the coordinates of the points that intersect the x-axis are (2, 0)
Here's your Answer....
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Since, It intersect at X axis.
Therefore, Y = 0.
6x - 4y = 12
6x - 4 × 0 = 12
6x = 12
x = 2.
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