Question

The line x-2y = 2 intersects the curve x+y2 = 10 at two points A and B. Find the equation of the perpendicular bisector of the line AB.

Answer 1

Step-by-step explanation:

y²+x = 10

x = 2 + 2y

y² +2y -8 =0

y² +4y -2y -8 =0

(y+4)(y-2) = 0

y = -4 or y = 2

x = -6 or x = 6

points are

(-4,-6) and (2,6)

Answer 2

Answer :

The equation of perpendicular bisector of the line AB is 2x+y+1=0

You can see step by step explaination answer in above pic which is attached by me.