Question

the line x+3y-5=0 is perpendicular to kx-y=7 then k is​

Answer 1

Answer:

The value of K is 3

Step-by-step explanation:

Concept :-

Two lines Perpendicular if m1×m2 = - 1

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Slope of x + 3y - 5 :-

=> X + 3y - 5 = 0

=> y = - x/3 + 5/3 (y = mx + c)

We get m1 = - 1/3

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Using property m1 × m2 = - 1

=> - 1/3 × m2 = - 1

=> m2 = 3

Thus ,

=> Y = kx + 7

=> k = m2

=> k = 3

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