Question

the line x/a-y/b=1 meets the X-axis at P. find the equation of the line perpendicular to this line at P.

Answer 1

use m1×m2=-1 for perpendicular lines........full solution is in pic

Answer 2

Answer:

The given line equation is,

x/a−y/b=1

y/b=x/a−1

y=(b/a)x−b

The slope of this line =b/a

So, the slope of the required line =−1/(b/a)=−a/b

Let the line intersect at point P(0,y) on the y-axis.

So, putting x=0 in the equation x/a−y/b=1, we get

0−y/b=1

y=−b

Hence, P=(0,−b)=(x

1

,y

1

)

Therefore,

The equation of the required line is

y−y

1

=m(x−x

1

)

y+b=(−a/b)(x−0)

by+b

2

=−ax

ax+by+b

2

=0