The line x = y touches a circle at the point (1, 1). If the circle also passes through the point (1, –3), then its radius is
(A) 3√2 (B) 3
(C) 2 (D) 2√2
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Option (B) 3 is the correct answer
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The line x = y touches a circle at the point (1, 1). If the circle also passes through the point (1, –3), then its radius is :
(D) 2√2
- The radius of the circle can be calculated as follows:
- We know that, Equation of circle can be represented as :
(x−1)² + (y−1)² + λ(x−y) = 0
- As per the question, passes through (1,3),
- Thus, 16 + λ(4) = 0
λ = −4
- So (x−1)² + (y−1)² − 4(x−y) = 0
x² + y² − 6x + 2y + 2 = 0
- Thus, r = 2√2
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