The line y = ax + b is parallel to the line y = 2x - 6 and passes through the point (-1, 7). Find the value of a and b.
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First we find the slope of the line 2x−3y+8=0 by placing it into slope intercept form:
2x−3y+8=0
⇒−3y=−2x−8
⇒3y=2x+8
⇒y=32x+38
Therefore, the slope of the line is m=32.
Now since the equation of the line with slope m passing through a point (x1,y1) is
y−y1=m(x−x1)
Here the point is (2,3) and slope is m=32, therefore, the equation of the line is:
y−3=32(x−2)⇒3(y−3)=2(x−2)⇒3y−9=2x−4⇒2x−3y=−9+4⇒2x−3y=−5
Hence, the equation of the line is 2x−3y=−5.
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