The line y = mx +1 is a tangent to the curve y2
= 4x if the value of mis
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Lets put y=mx+1 in y
2
=4x we get
(mx+1)
2
=4x
⇒m
2
x
2
+1+2mx−4x=0
Tangent touches a curve at one point so descriminant of the equation should be zero.
⇒(2m−4)
2
−4×1×m
2
=0
⇒4m
2
+16−16m−4m
2
=0
⇒m=1
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