Question

The linear charge density of the semi-circular ring on both sides is the same in magnitude. The electric fd intensity at O is along?

Answer 1

the electric field intensity due to the positive part is at 45° downward from positive x-axis and electric field intensity due to the negative part is at 45° upward from positive x-axis ... hence their resultant will be along positive x-axis ....
So... , the ans. is (1) i ....