Question

The linear congruence 18x = 6 (mod 3) has
a)Infinitely many solutions modulo 3 b)Finitely many solutions modulo 3
c)Unique solution modulo 3 d)Exactly three solutions modulo 3​

Answer 1

Answer:

d) exactly three solutions modulo 3

Answer 2

Answer:

D)Exactly has three solutions modulo 3

Step-by-step explanation:  

                       The linear congruence $ax=b(modn)$ has a solution if and only if d Divides b, where $d=gcd(a.n)$.if d Divides b then it has d mutually incongruent solution modulo n.--------$(1)$

  if $x_{0}$ is one of the solution of the congruence $ax=b(mod n)$ then the incongruent solutions are of the form $X_{0} ,x_{0} +\frac{n}{d} ,x_{0} +\frac{2n}{d}$...------$(2)$

  from the above two equations we can solve the solution as follows  

        The project code is     #SPJ3