The linear equation 2x - 5y = 7 has _________.
a. an unique solution b. two solutions
c. infinitely many solutions d. no solution
2. The equation x = 7, in two variables can be written as _________.
a. 1×x + 1× y = 7 b. 1×x + 0× y = 7
c. 0×x + 1× y = 7 d. 0×x + 0×y = 7
3. x = 5; y = 2 is a solution of the linear equation _________.
a. 7x +2y = 7 b. 5x +2y = 7
c. x + y = 7 d. 5x + y = 7
4. If a linear equation has solutions (-2, 2), (0, 0) and (2,-2), then it is of the
form ___________.
a. y - x = 0 b. x + y = 0
c. -2x + y = 0 d. -x + 2y = 0
5. The positive solutions of the equation ax + by + c = 0 always lie in the
___________.
a. I quadrant b. II quadrant
c. III quadrant d. IV quadrant
someone please ans plzzzzz
Answers
Answer:
1. ( infinite many solutions)
2.option b. is correct
3.(option c )x+y=7 is correct
4.option b x+y=0 is correct
5.in First quadrant.
Answer: 1. (c) 2.(c) 3(d) 4.(b) 5.(a)
Step by Step solution:
1. (c) In the given equation 2x – 5y = 7, for every value of x, we get a corresponding value of y and vice-versa. Therefore, the linear equation has infinitely many solutions.
2. (c)Here, the Coefficient of y in the given equation x =7 is 0. So, the equation can be written as 1-x + 0-y = 7
Hence, the required equation is 1x + 0.y = 7.
3. (d) x=5 , y=2
x+y=5+2(2)=9
5x+2y=5(5)+2(2)=29
x+y=7
5x+y=5(5)+2=27
x=5,y=2 is solution of x+y=7
4. (b)If a linear equation has solutions (-2,2)(0,0) and (2,-2), then it is of the form. Hence, x+y=0 is the required form of the linear equation.
5. (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the I quadrant are positive.