the linear equation 3x-4y=10 has
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3x+4y=10---(1)
x−y=1---(2)
Substitute the values of first option x=2 and y=1
In equations (1) and (2)
3(2)+4(1)=10
6+4=10
10=10
x−y=1
2−1=1
1=1
Therefore, the first option satisfied the linear equations.
Likewise substitute the value of second option x=1,y=1
3x+4y=10
3(1)+4(1)=10
7
=10
x−y=1
1−1=1
0
=1
Similarly, check the options to satisfy the linear equation.
Here, the first option satisfied the linear equation.
The solution is (2,1).
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