Question

The linear equation 3x-7y-12=0 and 14y-5x=15 has: *

please answer real quick​

Answer 1

Answer:

x=39

y=15

Step-by-step explanation:

3x-7y-12=0

or, 3x-7y=12-------eq(1)

14y-5x=15

or, -5x+14y=15-------eq(2)

adding both the eqs

3x-7y=12

+5x-14y=-15 (after we have changed the signs of

---------------- eq (2)

8x - 21y= -3(result of addition)

then, finding x

8x - 21y = -3

or, 8x=-3 +21y

or, x= (-3+21y)/8

putting the value of x in eq 1

3x-7y=12

or, 3{(-3+21y) /8}-7y=12

or,( -9+63y-56y) /8=12

or, (-9+7y) =12×8

or, 7y=96+9

or, y=105/7

y=15

putting the value of y in

x= (-3+21y)/8

or, x=(-3+21×15) /8

or, x=(-3+315) /8

or, x=312/8

x=39.

#you can also put the value of y in eq(2) to find out the value of x... either way same value will be the result .