Question

The lines 2x-3y+1=0 and 3x+ky-1=0 are perpendicular to each other if k =_________

Answer 1

Answer:

k = 2

Step-by-step explanation:

we have two eq. of line 2x-3y+1 = 0

and 3x+ky-1 = 0

as, the general equation of slope of line is, y = mx+c, where m is slope

so, express these eq. of line in the form of general equation...

y = 2x/3+1/3

and y = -3x/k+1/k comparing these two eq. with general equation.

so, M1 = 2/3

M2 = -3/k

as, there is relation between slope of two lines if they are perpendicular to each other i.e.,

M1M2 = -1

so, by putting these value,

(2/3)(-3/k) = -1

-2/k = -1

so, k = 2 .... ans.

Answer 2

Answer:

your answer is k = 2..........